Quadratic Equations and solving P(x)=0

            What is a quadratic, the general form  ax^2+bx+c

            Methods for solving ax^2+bx+c=0

            Why - because to find max and min values of functions we solve an equation equalling zero, also the 'roots' are the points 
                        where a function changes from negative to positive (loss to profit)

 Monday 14th & Tuesday 15th of Feb.

• solving by factorising    Nulake pg 240-243
• check your answers using the solve eqns on calculator
• completing the square pg 243/244

 Wednesday 16th Feb 

        The Solving Quadratics.ppt pg 247        

Thursday 17th Feb

        An Introduction to Limits -             

                    Consider the function f(x)=x^2+6x+8/(x+2), graph it - what is the value at f(-2)?

                    But how can their be a value at f(-2) that means we must be able to divide by zero (2=1)

                    How do we get around the problem of dividing by zero?

 
Also Homework from handout Ex 1.7 3 # 6-10           Ex 1.8 # 1-15 odd only   
                                            Ex 1.9 all                  Ex 1.10 all